Number Analogy Questions with solutions pdf
Arithmetic-based number analogy involves numbers that follow a specific arithmetic operation, such as addition, subtraction, multiplication, or division. The relationship between the first pair of numbers is applied to the second pair to find the missing number.
1️⃣ Addition-Based Analogy
2️⃣ Subtraction-Based Analogy
3️⃣ Multiplication-Based Analogy
4️⃣ Division-Based Analogy
5️⃣ Mixed Operations Analogy
✅ Check if numbers are related by addition/subtraction.
✅ If they are growing fast, check multiplication.
✅ If they are decreasing, check division.
✅ If no single rule works, try a combination of operations.
A square-based number analogy follows a pattern where numbers are related by squaring or square roots. The relationship between the first pair of numbers applies to the second pair.
1️⃣ Direct Squaring Analogy
2️⃣ Square Root Analogy
3️⃣ Square Number Difference Analogy
4️⃣ Sum of Square Digits Analogy
✅ If numbers are growing quickly, check squares.
✅ If numbers are decreasing, check square roots.
✅ If there’s a gap between numbers, check for square number differences.
✅ If digits are involved, check sum of squared digits.
A prime number analogy follows a pattern where numbers are either prime numbers themselves or related to prime numbers in some way. The relationship in the first pair of numbers is applied to the second pair to find the missing number.
1️⃣ Next Prime Number Analogy
2️⃣ Previous Prime Number Analogy
3️⃣ Prime Number Multiplication Analogy
4️⃣ Sum of Two Prime Numbers Analogy
5️⃣ Prime Number Position Analogy
✅ If the numbers are increasing or decreasing, check for next/previous prime numbers.
✅ If there is multiplication, check if both numbers are prime factors.
✅ If numbers are being added, check if they are sum of prime numbers.
✅ If positions matter, check the order of prime numbers (1st, 2nd, 3rd prime, etc.).
Q1: 6 : 18 :: 7 : ?
(A) 21
(B) 24
(C) 27
(D) 30
✅ Solution:
6×3=186 × 3 = 18, so 7×3=217 × 3 = 21
Answer: (A) 21
Q2: 4 : 16 :: 6 : ?
(A) 36
(B) 30
(C) 24
(D) 32
✅ Solution:
42=164^2 = 16, so 62=366^2 = 36
Answer: (A) 36
Q3: 3 : 27 :: 4 : ?
(A) 64
(B) 81
(C) 49
(D) 16
✅ Solution:
33=273^3 = 27, so 43=644^3 = 64
Answer: (A) 64
Q4: 2 : 3 :: 5 : ?
(A) 6
(B) 7
(C) 9
(D) 11
✅ Solution:
Next prime number after 2 is 3, and after 5 is 7
Answer: (B) 7
Q5: 21 : 12 :: 43 : ?
(A) 34
(B) 31
(C) 41
(D) 23
✅ Solution:
Reversing 21 → 12, so reversing 43 → 34
Answer: (A) 34
Q6: 35 : 8 :: 47 : ?
(A) 10
(B) 11
(C) 9
(D) 12
✅ Solution:
3+5=83 + 5 = 8, so 4+7=114 + 7 = 11
Answer: (B) 11
Q7: 2, 5, 4, 9, 6, ?
(A) 11
(B) 12
(C) 13
(D) 14
✅ Solution:
Odd positions: 2,4,62, 4, 6 (increasing by 2)
Even positions: 5,9,?5, 9, ? (increasing by 4)
Next term = 9 + 4 = 13
Answer: (C) 13
Q8: 2 : 2 :: 3 : 6 :: 4 : ?
(A) 24
(B) 12
(C) 8
(D) 16
✅ Solution:
2!=2,3!=6,4!=242! = 2, 3! = 6, 4! = 24
Answer: (A) 24
Q9: 1 : 1 :: 2 : 3 :: 3 : ?
(A) 5
(B) 6
(C) 4
(D) 7
✅ Solution:
Each number is the sum of the previous two.
1+1=21 + 1 = 2, 1+2=31 + 2 = 3, 2+3=52 + 3 = 5
Answer: (A) 5
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